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#18862: Fixing filtering menu items based on current culture

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Work Item: 18862

--HG--
branch : 1.x
This commit is contained in:
yermakovich
2012-09-19 17:09:55 -07:00
parent c11206a57e
commit acdd97a35d
1 changed files with 12 additions and 2 deletions
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src/Orchard.Web/Core/Navigation/Services/DefaultMenuProvider.cs
+11 -1
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@@ -24,12 +24,22 @@ namespace Orchard.Core.Navigation.Services {
if (menuPart != null) { if (menuPart != null) {
var part = menuPart; var part = menuPart;
// fetch the culture of the menu item, if any
string culture = null; string culture = null;
// fetch the culture of the content menu item, if any
var localized = part.As<ILocalizableAspect>(); var localized = part.As<ILocalizableAspect>();
if (localized != null) { if (localized != null) {
culture = localized.Culture; culture = localized.Culture;
} }
else {
// fetch the culture of the content menu item, if any
var contentMenuItemPart = part.As<ContentMenuItemPart>();
if (contentMenuItemPart != null) {
localized = contentMenuItemPart.Content.As<ILocalizableAspect>();
if (localized != null) {
culture = localized.Culture;
}
}
}
if (part.Is<MenuItemPart>()) if (part.Is<MenuItemPart>())
builder.Add(new LocalizedString(HttpUtility.HtmlEncode(part.MenuText)), part.MenuPosition, item => item.Url(part.As<MenuItemPart>().Url).Content(part).Culture(culture)); builder.Add(new LocalizedString(HttpUtility.HtmlEncode(part.MenuText)), part.MenuPosition, item => item.Url(part.As<MenuItemPart>().Url).Content(part).Culture(culture));