🐛 #1777 XML工具类修复无法解析<ExtAttr><Item>这种节点数据的问题

This commit is contained in:
giveme0101
2020-09-24 14:31:10 +08:00
committed by Binary Wang
parent 807ed7d0b5
commit e0c995e1f8

View File

@@ -3,10 +3,7 @@ package me.chanjar.weixin.common.util;
import com.google.common.collect.Lists; import com.google.common.collect.Lists;
import com.google.common.collect.Maps; import com.google.common.collect.Maps;
import com.google.common.collect.Sets; import com.google.common.collect.Sets;
import org.dom4j.Document; import org.dom4j.*;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.Node;
import org.dom4j.io.SAXReader; import org.dom4j.io.SAXReader;
import org.dom4j.tree.DefaultText; import org.dom4j.tree.DefaultText;
import org.xml.sax.SAXException; import org.xml.sax.SAXException;
@@ -50,14 +47,16 @@ public class XmlUtils {
} }
private static Object element2MapOrString(Element element) { private static Object element2MapOrString(Element element) {
Map<String, Object> result = Maps.newHashMap();
final List<Node> content = element.content(); final List<Node> content = element.content();
if (content.size() <= 1) { final Set<String> names = names(content);
// 判断节点下有无非文本节点(非Text和CDATA)如无直接取Text文本内容
if (names.size() < 1) {
return element.getText(); return element.getText();
} }
final Set<String> names = names(content); Map<String, Object> result = Maps.newHashMap();
if (names.size() == 1) { if (names.size() == 1) {
// 说明是个列表各个子对象是相同的name // 说明是个列表各个子对象是相同的name
List<Object> list = Lists.newArrayList(); List<Object> list = Lists.newArrayList();
@@ -90,7 +89,8 @@ public class XmlUtils {
private static Set<String> names(List<Node> nodes) { private static Set<String> names(List<Node> nodes) {
Set<String> names = Sets.newHashSet(); Set<String> names = Sets.newHashSet();
for (Node node : nodes) { for (Node node : nodes) {
if (node instanceof DefaultText) { // 如果节点类型是Text或CDATA跳过
if (node instanceof DefaultText || node instanceof CDATA) {
continue; continue;
} }
names.add(node.getName()); names.add(node.getName());