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https://gitee.com/dromara/hutool.git
synced 2026-02-09 09:16:26 +08:00
fix(Arrangement): improve count and select methods with overflow checks and enhance documentation
This commit is contained in:
@@ -1,12 +1,9 @@
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package cn.hutool.core.math;
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import java.io.Serializable;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.List;
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import cn.hutool.core.util.ArrayUtil;
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import cn.hutool.core.util.NumberUtil;
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import java.io.Serializable;
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import java.util.*;
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/**
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* 排列A(n, m)<br>
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@@ -47,10 +44,23 @@ public class Arrangement implements Serializable {
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* @return 排列数
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*/
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public static long count(int n, int m) {
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if (n == m) {
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return NumberUtil.factorial(n);
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if (m < 0 || m > n) {
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throw new IllegalArgumentException("n >= 0 && m >= 0 && m <= n required");
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}
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return (n > m) ? NumberUtil.factorial(n, n - m) : 0;
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if (m == 0) {
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return 1;
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}
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long result = 1;
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// 从 n 到 n-m+1 逐个乘
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for (int i = 0; i < m; i++) {
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long next = result * (n - i);
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// 溢出检测
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if (next < result) {
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throw new ArithmeticException("Overflow computing A(" + n + "," + m + ")");
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}
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result = next;
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}
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return result;
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}
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/**
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@@ -77,26 +87,85 @@ public class Arrangement implements Serializable {
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}
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/**
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* 排列选择(从列表中选择m个排列)
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* 从当前数据中选择 m 个元素,生成所有「不重复」的排列(Permutation)。
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*
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* @param m 选择个数
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* @return 所有排列列表
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* <p>
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* 说明:
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* <ul>
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* <li>不允许重复选择同一个元素(即经典排列 A(n, m))</li>
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* <li>结果中不会出现 ["1","1"] 这种重复元素的情况</li>
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* <li>顺序敏感,因此 ["1","2"] 与 ["2","1"] 都会包含</li>
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* </ul>
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*
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* 数量公式:
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* <pre>
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* A(n, m) = n! / (n - m)!
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* </pre>
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*
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* 举例:
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* <pre>
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* datas = ["1","2","3"]
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* m = 2
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* 输出:
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* ["1","2"]
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* ["1","3"]
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* ["2","1"]
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* ["2","3"]
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* ["3","1"]
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* ["3","2"]
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* 共 6 个(A(3,2)=6)
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* </pre>
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*
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* @param m 选择的元素个数
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* @return 所有长度为 m 的不重复排列列表
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*/
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public List<String[]> select(int m) {
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final List<String[]> result = new ArrayList<>((int) count(this.datas.length, m));
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select(this.datas, new String[m], 0, result);
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if (m < 0 || m > datas.length) {
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return Collections.emptyList();
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}
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if (m == 0) {
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// A(n,0) = 1,唯一一个空排列
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return Collections.singletonList(new String[0]);
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}
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long estimated = count(datas.length, m);
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int capacity = estimated > Integer.MAX_VALUE ? Integer.MAX_VALUE : (int) estimated;
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List<String[]> result = new ArrayList<>(capacity);
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boolean[] visited = new boolean[datas.length];
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dfs(new String[m], 0, visited, result);
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return result;
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}
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/**
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* 排列所有组合,即A(n, 1) + A(n, 2) + A(n, 3)...
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* 生成当前数据的全部不重复排列(长度为 1 至 n 的所有排列)。
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*
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* @return 全排列结果
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* <p>
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* 说明:
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* <ul>
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* <li>不允许重复选择元素(无 ["1","1"],无 ["2","2","3"] 这种)</li>
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* <li>包含所有长度 m=1..n 的排列</li>
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* <li>总数量为 A(n,1) + A(n,2) + ... + A(n,n)</li>
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* </ul>
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*
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* 举例(datas = ["1","2","3"]):
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* <pre>
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* m=1: ["1"], ["2"], ["3"] → 3 个
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* m=2: ["1","2"], ["1","3"], ["2","1"], ... → 6 个
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* m=3: ["1","2","3"], ["1","3","2"], ["2","1","3"], ...→ 6 个
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*
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* 总共:3 + 6 + 6 = 15
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* </pre>
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*
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* @return 所有不重复排列列表
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*/
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public List<String[]> selectAll() {
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final List<String[]> result = new ArrayList<>((int) countAll(this.datas.length));
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for (int i = 1; i <= this.datas.length; i++) {
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result.addAll(select(i));
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List<String[]> result = new ArrayList<>();
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for (int m = 1; m <= datas.length; m++) {
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result.addAll(select(m));
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}
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return result;
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}
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@@ -124,4 +193,113 @@ public class Arrangement implements Serializable {
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select(ArrayUtil.remove(datas, i), resultList, resultIndex + 1, result);
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}
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}
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/**
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* 返回一个排列的迭代器
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*
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* @param m 选择的元素个数
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* @return 排列迭代器
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*/
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public Iterable<String[]> iterate(int m) {
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return () -> new ArrangementIterator(datas, m);
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}
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/**
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* 排列迭代器
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*
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* @author CherryRum
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*/
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private static class ArrangementIterator implements Iterator<String[]> {
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private final String[] datas;
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private final int m;
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private final boolean[] visited;
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private final String[] buffer;
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private final Deque<Integer> stack = new ArrayDeque<>();
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boolean end = false;
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ArrangementIterator(String[] datas, int m) {
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this.datas = datas;
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this.m = m;
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this.visited = new boolean[datas.length];
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this.buffer = new String[m];
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// 初始化 dfs 栈
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stack.push(0);
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}
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@Override
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public boolean hasNext() {
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return !end;
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}
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@Override
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public String[] next() {
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while (!stack.isEmpty()) {
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int depth = stack.size() - 1;
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int idx = stack.pop();
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if (idx >= datas.length) {
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// 这一层遍历结束
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if (!stack.isEmpty()) {
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int prev = stack.pop();
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stack.push(prev + 1);
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}
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continue;
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}
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// 如果该元素未使用
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if (!visited[idx]) {
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visited[idx] = true;
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buffer[depth] = datas[idx];
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if (depth == m - 1) {
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// 输出一个排列
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visited[idx] = false;
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// 下一次从 idx+1 继续
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stack.push(idx + 1);
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return Arrays.copyOf(buffer, m);
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} else {
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// 继续下一层
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stack.push(idx + 1); // 当前层下一个起点
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stack.push(0); // 下一层起点
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continue;
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}
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}
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// 已访问则跳过
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stack.push(idx + 1);
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}
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end = true;
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return null;
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}
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}
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/**
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* 核心递归方法(回溯算法)
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* * @param current 当前构建的排列数组
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*
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* @param depth 当前递归深度(填到了第几个位置)
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* @param visited 标记数组,记录哪些索引已经被使用了
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* @param result 结果集
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*/
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private void dfs(String[] current, int depth, boolean[] visited, List<String[]> result) {
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if (depth == current.length) {
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result.add(Arrays.copyOf(current, current.length));
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return;
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}
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for (int i = 0; i < datas.length; i++) {
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if (!visited[i]) {
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visited[i] = true;
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current[depth] = datas[i];
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dfs(current, depth + 1, visited, result);
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visited[i] = false;
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}
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}
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}
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}
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@@ -1,20 +1,22 @@
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package cn.hutool.core.math;
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import cn.hutool.core.lang.Console;
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import org.junit.jupiter.api.Disabled;
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import org.junit.jupiter.api.Test;
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import java.util.List;
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import static org.junit.jupiter.api.Assertions.*;
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import org.junit.jupiter.api.Disabled;
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import org.junit.jupiter.api.Test;
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import cn.hutool.core.lang.Console;
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/**
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* 排列单元测试
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* @author looly
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*
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*/
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public class ArrangementTest {
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// ----------------------------------------------------
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// 基础测试
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// ----------------------------------------------------
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@Test
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public void arrangementTest() {
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long result = Arrangement.count(4, 2);
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@@ -30,37 +32,117 @@ public class ArrangementTest {
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assertEquals(64, resultAll);
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}
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// ----------------------------------------------------
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// select 基础测试
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// ----------------------------------------------------
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@Test
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public void selectTest() {
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Arrangement arrangement = new Arrangement(new String[] { "1", "2", "3", "4" });
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Arrangement arrangement = new Arrangement(new String[]{"1", "2", "3", "4"});
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List<String[]> list = arrangement.select(2);
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assertEquals(Arrangement.count(4, 2), list.size());
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assertArrayEquals(new String[] {"1", "2"}, list.get(0));
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assertArrayEquals(new String[] {"1", "3"}, list.get(1));
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assertArrayEquals(new String[] {"1", "4"}, list.get(2));
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assertArrayEquals(new String[] {"2", "1"}, list.get(3));
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assertArrayEquals(new String[] {"2", "3"}, list.get(4));
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assertArrayEquals(new String[] {"2", "4"}, list.get(5));
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assertArrayEquals(new String[] {"3", "1"}, list.get(6));
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assertArrayEquals(new String[] {"3", "2"}, list.get(7));
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assertArrayEquals(new String[] {"3", "4"}, list.get(8));
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assertArrayEquals(new String[] {"4", "1"}, list.get(9));
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assertArrayEquals(new String[] {"4", "2"}, list.get(10));
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assertArrayEquals(new String[] {"4", "3"}, list.get(11));
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// 校验数量一致
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assertEquals(Arrangement.count(4, 2), list.size());
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// 逐项严格校验顺序是否一致(按 DFS 顺序)
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assertArrayEquals(new String[]{"1", "2"}, list.get(0));
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assertArrayEquals(new String[]{"1", "3"}, list.get(1));
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assertArrayEquals(new String[]{"1", "4"}, list.get(2));
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assertArrayEquals(new String[]{"2", "1"}, list.get(3));
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assertArrayEquals(new String[]{"2", "3"}, list.get(4));
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assertArrayEquals(new String[]{"2", "4"}, list.get(5));
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assertArrayEquals(new String[]{"3", "1"}, list.get(6));
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assertArrayEquals(new String[]{"3", "2"}, list.get(7));
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assertArrayEquals(new String[]{"3", "4"}, list.get(8));
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assertArrayEquals(new String[]{"4", "1"}, list.get(9));
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assertArrayEquals(new String[]{"4", "2"}, list.get(10));
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assertArrayEquals(new String[]{"4", "3"}, list.get(11));
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// 测试 selectAll
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List<String[]> selectAll = arrangement.selectAll();
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assertEquals(Arrangement.countAll(4), selectAll.size());
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// m=0,应该返回一个空排列
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List<String[]> list2 = arrangement.select(0);
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assertEquals(1, list2.size());
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assertEquals(0, list2.get(0).length);
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}
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// ----------------------------------------------------
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// 扩展测试:边界、错误处理
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// ----------------------------------------------------
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@Test
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@Disabled
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public void selectTest2() {
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List<String[]> list = MathUtil.arrangementSelect(new String[] { "1", "1", "3", "4" });
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for (String[] strings : list) {
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Console.log(strings);
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public void boundaryTest() {
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Arrangement arr = new Arrangement(new String[]{"A", "B", "C"});
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// m = n
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List<String[]> full = arr.select(3);
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assertEquals(6, full.size());
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// m = 1
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List<String[]> one = arr.select(1);
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assertEquals(3, one.size());
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assertArrayEquals(new String[]{"A"}, one.get(0));
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// m > n → empty list
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assertTrue(arr.select(10).isEmpty());
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// m < 0 → empty list
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assertTrue(arr.select(-1).isEmpty());
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}
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// ----------------------------------------------------
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// 扩展测试:空数组
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// ----------------------------------------------------
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@Test
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public void emptyTest() {
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Arrangement arrangement = new Arrangement(new String[]{});
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assertEquals(1, arrangement.select(0).size());
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assertTrue(arrangement.select(1).isEmpty());
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assertTrue(arrangement.selectAll().isEmpty()); // A(0,m) = 0 for m>0,A(0,0)=1 → 全排列 = 1 个空排列
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}
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// ----------------------------------------------------
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// 扩展测试:重复元素(用于验证去重算法)
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// 默认 Arrangement 不去重,因此应该包含重复排列
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// ----------------------------------------------------
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@Test
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@Disabled("默认 Arrangement 不支持去重;启用后手动检查")
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public void duplicateElementTest() {
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Arrangement arrangement = new Arrangement(new String[]{"1", "1", "3"});
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List<String[]> list = arrangement.select(2);
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// 应该有 A(3,2) = 6 个
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assertEquals(6, list.size());
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for (String[] s : list) {
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Console.log(s);
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}
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}
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// ----------------------------------------------------
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// 扩展测试:selectAll 覆盖全部不重复排列(A(n,1..n))
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// ----------------------------------------------------
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@Test
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public void selectAllTest() {
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Arrangement arrangement = new Arrangement(new String[]{"1", "2", "3"});
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List<String[]> all = arrangement.selectAll();
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// 打印用于观测
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for (String[] s : all) {
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Console.log(s);
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}
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// A(3,1) + A(3,2) + A(3,3) = 3 + 6 + 6 = 15
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assertEquals(Arrangement.countAll(3), all.size());
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assertEquals(15, all.size());
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// spot check 不重复排列
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assertArrayEquals(new String[]{"1"}, all.get(0));
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assertArrayEquals(new String[]{"1", "2"}, all.get(3));
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assertArrayEquals(new String[]{"1", "2", "3"}, all.get(9));
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}
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}
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