修复SqlUtil.PATTERN_IN_CLAUSE逻辑缺陷导致in语句参数不正确的问题（pr#4203@Github）

hutool-db/src/main/java/cn/hutool/v7/db/sql/SqlUtil.java

@@ -49,7 +49,7 @@ public class SqlUtil {
 	/**
 	 * SQL中的in语句部分的正则
 	 */
-	private static final Pattern PATTERN_IN_CLAUSE = PatternPool.get("\\s+in\\s+[(]", Pattern.CASE_INSENSITIVE);
+	private static final Pattern PATTERN_IN_CLAUSE = PatternPool.get("\\s+in\\s+[(]\\s*$", Pattern.CASE_INSENSITIVE);
 
 	/**
 	 * 构件相等条件的where语句<br>

hutool-db/src/test/java/cn/hutool/v7/db/sql/Issue4200Test.java

@@ -0,0 +1,68 @@
+package cn.hutool.v7.db.sql;
+
+import org.junit.jupiter.api.Test;
+
+import static org.junit.jupiter.api.Assertions.assertFalse;
+import static org.junit.jupiter.api.Assertions.assertTrue;
+
+public class Issue4200Test {
+	/**
+	 * issues中提及的SQL
+	 */
+	private final static String TEST_SQL = "select case when  1 in (1) and 2 = any(:number) then 1 else 0 end";
+
+
+	/**
+	 * 基础测试：in子句测试
+	 */
+	@Test
+	public void isInClauseTest0() {
+		final String sql = "select case when 1=1 and 2 in ( ";
+		assertTrue(SqlUtil.isInClause(sql));
+	}
+
+	/**
+	 * 基础测试：in子句测试
+	 */
+	@Test
+	public void isInClauseTest1() {
+		final String sql = "select case when 1=1 and 2 in (";
+		assertTrue(SqlUtil.isInClause(sql));
+	}
+
+	/**
+	 * 基础测试：非in子句测试
+	 */
+	@Test
+	public void isInClauseTest2() {
+		// 测试基本的ORDER BY移除
+		//final String sql = "select case when  1 in (1) and 2 = any(:number) then 1 else 0 end";
+		final String sql = "select case when 1=1 and 2 = any(";
+
+		assertFalse(SqlUtil.isInClause(sql));
+	}
+
+	/**
+	 * 测试 包含in但非param对应的in子句测试
+	 */
+	@Test
+	public void isInClauseTest3() {
+		// 截断前sql
+		//final String sql =
+		final String sql = "select case when 1 in (?,?,?) and 2 = any(";
+
+		assertFalse(SqlUtil.isInClause(sql));
+	}
+
+	/**
+	 * 测试 包含in但非param对应的in子句测试
+	 */
+	@Test
+	public void isInClauseTest4() {
+		// 截断前sql
+		//final String sql =
+		final String sql = "select case when 1 in (?,?,?) and 2 = any(";
+
+		assertFalse(SqlUtil.isInClause(sql));
+	}
+}